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What is the total entropy change of the universe for?
Consider three engines that each use 1650 J of heat from a hot resevoir (temperature = 550 K). These three engines reject heat to a cold resevoir (temperature 330 K). Engine I rejects 1350 J of heat. Engine II rejects 990 J of heat. Engine III rejects 580 J of heat. One of the engines operates reversibly, and two operate irreversibly. However, of the two irreversible engines, one violates the second law of thermodynamics and could not exist. What is the total entropy change of the universe for (a) engine I, (b) engine II, and (c) engine III? (Note: The total entropy change of the universe is the sum of the entropy changes of the hot and cold resevoirs.)
Dear Bill,
For the total change in the Entropy of the universe, work out the entropy change S = DQ/T for the two reservoirs.
DQhigh = 4050
DShigh= 4050/550
DQlow = 2820 Joules
DSlow = 2920 J/K
The difference gives either the maximum or minimum chandge of entropy in the Universe.
Argue it out through the logic of the situation.
These calculations are standard advanced level textbook ones. Look it up in the books suggested for your Course.
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